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What is the minimum distance between two points in water that are π/3 rad out of phase if the frequency is 2500 Hz?

0.05 m

0.1 m

To find the minimum distance between two points in water that are π/3 radians out of phase at a frequency of 2500 Hz, we start by determining the wavelength of the wave in water.

The speed of sound in water is approximately 1500 m/s. The relationship between speed (v), frequency (f), and wavelength (λ) is given by the equation:

\[ v = f \cdot \lambda \]

Rearranging this formula allows us to find the wavelength:

\[ \lambda = \frac{v}{f} = \frac{1500 \, \text{m/s}}{2500 \, \text{Hz}} = 0.6 \, \text{m} \]

Next, to find the minimum distance between two points that are π/3 radians out of phase, we relate the phase difference to the distance. The phase difference, in radians, can be expressed in terms of the wavelength as follows:

\[ \text{Phase Difference} = \frac{2\pi}{\lambda} \cdot d \]

Where \( d \) is the distance. For a phase difference of π/3 radians, we set up the equation:

\[ \frac{2\

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